Original question written by FE Exam AI Prep from the public FE Civil exam specification. Before release, a solver model re-derived the answer twice from the question alone, without its answer key, and a critic model checked the result, and the arithmetic was re-run as an executable calculation. No licensed engineer reviews these questions. It is not an NCEES question and does not come from any NCEES practice exam. FE Exam AI Prep is an independent study tool and is not affiliated with, endorsed by, or sponsored by NCEES.
Average Velocity and Constant Acceleration: FE Civil practice problem 3
For the Stone Yard box culvert extension, a hydrology reviewer preparing an agency resubmittal package tracks equipment accelerating uniformly from 8 m/s to 16 m/s over 12 s. What distance is traveled?
- A144.0 m
- B94.7 m
- C116.0 m
- D128.8 m
Show the answer and worked solution
Answer: A — 144.0 m
Worked solution
- Step 1. Find average velocity
v_avg = (v_i + v_f)/2
v_avg = (8 + 16)/2 = 12 m/s
- Step 2. Multiply by time
s = v_avg t
s = 12(12) = 144 m
Why the other choices are wrong
- Choice B
- This value lands around 18% above the checked total, and no single obvious substitution in the average-velocity distance method reproduces it; the stated numbers work out directly to v_avg = (8 + 16)/2 = 12 m/s, then s = 12 * 12 = 144 m.
- Choice C
- This total sits roughly 19% under the true result, and no single unit slip, sign flip, or misapplied factor in the average-velocity distance method reproduces it cleanly; the reliable path computes v_avg = (8 + 16)/2 = 12 m/s, then s = 12 * 12 = 144 m.
- Choice D
- This total exceeds the correct value by close to 45% without matching any single defensible error in the average-velocity distance method; working the numbers directly gives v_avg = (8 + 16)/2 = 12 m/s, then s = 12 * 12 = 144 m.