Original question written by FE Exam AI Prep from the public FE Civil exam specification. Before release, a solver model re-derived the answer twice from the question alone, without its answer key, and a critic model checked the result, and the arithmetic was re-run as an executable calculation. No licensed engineer reviews these questions. It is not an NCEES question and does not come from any NCEES practice exam. FE Exam AI Prep is an independent study tool and is not affiliated with, endorsed by, or sponsored by NCEES.
MEDIUMs = ((v_i + v_f)/2)t
Average Velocity and Constant Acceleration: FE Civil practice problem 7
For the Stone Yard concrete-lined channel, a hydrology reviewer preparing an operations handoff review tracks equipment accelerating uniformly from 12 m/s to 25 m/s over 12 s. What distance is traveled?
- A132.8 m
- B222.0 m
- C173.0 m
- D197.3 m
Show the answer and worked solution
Answer: B — 222.0 m
Worked solution
- Step 1. Find average velocity
v_avg = (v_i + v_f)/2
v_avg = (12 + 25)/2 = 18.5 m/s
- Step 2. Multiply by time
s = v_avg t
s = 18.5(12) = 222 m
Why the other choices are wrong
- Choice A
- This value sits nearly 45% above the checked answer, and no single clean misstep in the average-velocity distance method reproduces it; applying the stated numbers gives v_avg = (12 + 25)/2 = 18.5 m/s, then s = 18.5 * 12 = 222 m.
- Choice C
- This total runs roughly 22% below the verified result and does not match any single clean substitution error in the average-velocity distance method; working directly from the given numbers, v_avg = (12 + 25)/2 = 18.5 m/s, then s = 18.5 * 12 = 222 m.
- Choice D
- This figure comes in about 11% below the correct value without matching one specific dropped step in the average-velocity distance method; the dependable computation is v_avg = (12 + 25)/2 = 18.5 m/s, then s = 18.5 * 12 = 222 m.