Original question written by FE Exam AI Prep from the public FE Civil exam specification. Before release, a solver model re-derived the answer twice from the question alone, without its answer key, and a critic model checked the result, and the arithmetic was re-run as an executable calculation. No licensed engineer reviews these questions. It is not an NCEES question and does not come from any NCEES practice exam. FE Exam AI Prep is an independent study tool and is not affiliated with, endorsed by, or sponsored by NCEES.
MEDIUMs = ((v_i + v_f)/2)t
Average Velocity and Constant Acceleration: FE Civil practice problem 2
For the Stone Yard arterial overlay, a hydrology reviewer preparing an agency resubmittal package tracks equipment accelerating uniformly from 10 m/s to 19 m/s over 12 s. What distance is traveled?
- A196.6 m
- B220.7 m
- C262.7 m
- D174.0 m
Show the answer and worked solution
Answer: D — 174.0 m
Worked solution
- Step 1. Find average velocity
v_avg = (v_i + v_f)/2
v_avg = (10 + 19)/2 = 14.5 m/s
- Step 2. Multiply by time
s = v_avg t
s = 14.5(12) = 174 m
Why the other choices are wrong
- Choice A
- 205.3 m cannot be traced back to one clean slip in the average-velocity method; working the relation s = (v_i + v_f)/2 * t through these numbers gives 174.0 m as the traveled distance.
- Choice B
- 135.7 m does not correspond to one identifiable substitution error worked through the average-velocity relation; the governing calculation is s = (v_i + v_f)/2 * t, which returns 174.0 m for these endpoint speeds and duration.
- Choice C
- 252.3 m sits well outside what one clean substitution mistake would produce here; the defensible answer comes from s = (v_i + v_f)/2 * t, evaluated with v_i = 10 m/s, v_f = 19 m/s, and t = 12 s to give 174.0 m.