Original question written by FE Exam AI Prep from the public FE Civil exam specification. Before release, a solver model re-derived the answer twice from the question alone, without its answer key, and a critic model checked the result, and the arithmetic was re-run as an executable calculation. No licensed engineer reviews these questions. It is not an NCEES question and does not come from any NCEES practice exam. FE Exam AI Prep is an independent study tool and is not affiliated with, endorsed by, or sponsored by NCEES.
Average Velocity and Constant Acceleration: FE Civil practice problem 6
For the Iron Ridge box culvert extension, a hydrology reviewer preparing a field-change evaluation tracks equipment accelerating uniformly from 11 m/s to 21 m/s over 10 s. What distance is traveled?
- A160.0 m
- B175.1 m
- C192.5 m
- D219.7 m
Show the answer and worked solution
Answer: A — 160.0 m
Worked solution
- Step 1. Find average velocity
v_avg = (v_i + v_f)/2
v_avg = (11 + 21)/2 = 16 m/s
- Step 2. Multiply by time
s = v_avg t
s = 16(10) = 160 m
Why the other choices are wrong
- Choice B
- This total runs roughly 9% above the verified result and does not match any single clean substitution error in the average-velocity distance method; working directly from the given numbers, v_avg = (11 + 21)/2 = 16 m/s, then s = 16 * 10 = 160 m.
- Choice C
- This figure comes in about 20% above the correct value without matching one specific dropped step in the average-velocity distance method; the dependable computation is v_avg = (11 + 21)/2 = 16 m/s, then s = 16 * 10 = 160 m.
- Choice D
- This number runs about 37% over the verified total and does not correspond to one identifiable substitution mistake in the average-velocity distance method; the direct computation is v_avg = (11 + 21)/2 = 16 m/s, then s = 16 * 10 = 160 m.