Original question written by FE Exam AI Prep from the public FE Civil exam specification. Before release, a solver model re-derived the answer twice from the question alone, without its answer key, and a critic model checked the result, and the arithmetic was re-run as an executable calculation. No licensed engineer reviews these questions. It is not an NCEES question and does not come from any NCEES practice exam. FE Exam AI Prep is an independent study tool and is not affiliated with, endorsed by, or sponsored by NCEES.
MEDIUMs = ((v_i + v_f)/2)t
Average Velocity and Constant Acceleration: FE Civil practice problem 5
For the Stone Yard arterial overlay, a hydrology reviewer preparing an asset management screening tracks equipment accelerating uniformly from 10 m/s to 24 m/s over 8 s. What distance is traveled?
- A149.2 m
- B164.4 m
- C205.8 m
- D136.0 m
Show the answer and worked solution
Answer: D — 136.0 m
Worked solution
- Step 1. Find average velocity
v_avg = (v_i + v_f)/2
v_avg = (10 + 24)/2 = 17 m/s
- Step 2. Multiply by time
s = v_avg t
s = 17(8) = 136 m
Why the other choices are wrong
- Choice A
- This figure comes out about 10% higher than the correct value without tracing to one specific dropped or altered step in the average-velocity distance method; the dependable computation is v_avg = (10 + 24)/2 = 17 m/s, then s = 17 * 8 = 136 m.
- Choice B
- This number falls close to 22% short of the verified total and cannot be traced to a single clean arithmetic slip in the average-velocity distance method; applying the given numbers directly gives v_avg = (10 + 24)/2 = 17 m/s, then s = 17 * 8 = 136 m.
- Choice C
- This value sits nearly 45% above the checked answer, and no single clean misstep in the average-velocity distance method reproduces it; applying the stated numbers gives v_avg = (10 + 24)/2 = 17 m/s, then s = 17 * 8 = 136 m.