Original question written by FE Exam AI Prep from the public FE Civil exam specification. Before release, a solver model re-derived the answer twice from the question alone, without its answer key, and a critic model checked the result, and the arithmetic was re-run as an executable calculation. No licensed engineer reviews these questions. It is not an NCEES question and does not come from any NCEES practice exam. FE Exam AI Prep is an independent study tool and is not affiliated with, endorsed by, or sponsored by NCEES.
MEDIUMs = ((v_i + v_f)/2)t
Average Velocity and Constant Acceleration: FE Civil practice problem 8
For the Iron Ridge arterial overlay, a hydrology reviewer preparing a quality-control closeout tracks equipment accelerating uniformly from 4 m/s to 13 m/s over 6 s. What distance is traveled?
- A56.0 m
- B65.8 m
- C72.3 m
- D51.0 m
Show the answer and worked solution
Answer: D — 51.0 m
Worked solution
- Step 1. Find average velocity
v_avg = (v_i + v_f)/2
v_avg = (4 + 13)/2 = 8.5 m/s
- Step 2. Multiply by time
s = v_avg t
s = 8.5(6) = 51 m
Why the other choices are wrong
- Choice A
- This number sits close to 18% over the true answer and cannot be pinned to a single well-defined arithmetic slip in the average-velocity distance method; applying the numbers exactly as given yields v_avg = (4 + 13)/2 = 8.5 m/s, then s = 8.5 * 6 = 51 m.
- Choice B
- This value lands around 22% under the checked total, and no obvious single substitution in the average-velocity distance method reproduces it; the stated numbers work out directly to v_avg = (4 + 13)/2 = 8.5 m/s, then s = 8.5 * 6 = 51 m.
- Choice C
- This figure lands roughly 42% above the true result and cannot be traced to one clean computational misstep in the average-velocity distance method; the dependable calculation evaluates to v_avg = (4 + 13)/2 = 8.5 m/s, then s = 8.5 * 6 = 51 m.